Multimagic series for cubes
See also the
multimagic series for squares
As we have seen for the smallest bimagic cube, it may be interesting, in order to try to construct a p-multimagic cube of order-n, to find all the p-multimagic series of order n, that is to say the series of n different integers, from 1 to n3, having the correct magic, bimagic,... until p-multimagic sums (= S1, S2,... Sp):
The order 3 allows to get bimagic series. Here are the 4 possible bimagic series:
So that means that:
For the order 4, there are 8 bimagic series for which the list is given in the Smallest bimagic cube page.
Here is a summary of the number of multimagic series, some of these lists being downloadable as Excel files, from 44Kb to 540Kb each. The numbers of bimagic series of order 9 and 10 were computed by Walter Trump, Germany, in October 2005. The number of trimagic series of order 9 was computed by Gildas Guillemot, France, in December 2006 and later confirmed by Michael Quist, USA, in May 2008.
|
Order |
Bimagic |
Trimagic |
Tetramagic |
|
3 |
4 |
0 |
0 |
|
4 |
0 |
0 |
|
|
5 |
0 |
0 |
|
|
6 |
(*) 0 |
0 |
|
|
7 |
5 152 529 |
0 |
|
|
8 |
1 594 825 624 |
0 |
|
|
9 |
651 151 145 259 |
363 949 |
(**) 0 |
|
10 |
347 171 191 981 324 |
(*) 0 |
0 |
|
11 |
Unknown! Look at the unresolved problems |
||
(*) Trimagic series of order 4k+2 are impossible: it is
impossible to have S3 even, with S1 odd and S2 odd.
(**) Short and
nice proof by Robert Gerbicz, Hungary, in January 2006. "For the order 9, the tetramagic sum is S4=510,118,152,189==13 mod 16.
But (2*x+1)^4==1 mod 16 and (2*x)^4==0 mod 16: it means that at least
13 odd numbers are needed. Impossible with only 9 numbers!"
The bimagic and trimagic series are referenced respectively under the numbers A090653 and A092312 in the Neil Sloane's Encyclopedia of Integer Sequences, AT&T Research.
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